m2=0.610−2.0m sub 2 equals the fraction with numerator 0.6 and denominator 10 minus 2.0 end-fraction m2=0.68.0m sub 2 equals 0.6 over 8.0 end-fraction m2=0.075 kgm sub 2 equals 0.075 kg 🏁 Final Answer The tension in the string is and the mass of the second object is
Since the first object is resting on a smooth horizontal table, the only horizontal force acting on it is the tension of the string.Using Newton's second law ( ) for the first object: T=m1⋅acap T equals m sub 1 center dot a Substitute the known values: teen streap
T=0.3 kg⋅2.0 m/s2cap T equals 0.3 kg center dot 2.0 m/s squared T=0.6 Ncap T equals 0.6 N 3. Analyze the forces on the second object AI responses may include mistakes
m2=Tg−am sub 2 equals the fraction with numerator cap T and denominator g minus a end-fraction Substitute the values into the equation: consult a professional.
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