Reshebnik A.ershova V.v.goloborodko K-4 Umnozhenie Drobei 6 Klass Resheniia Apr 2026

3×32×2=94=214the fraction with numerator 3 cross 3 and denominator 2 cross 2 end-fraction equals nine-fourths equals 2 and one-fourth

(12)2×113open paren one-half close paren squared cross 1 and one-third : 3×32×2=94=214the fraction with numerator 3 cross 3 and

1×15×3=115the fraction with numerator 1 cross 1 and denominator 5 cross 3 end-fraction equals 1 over 15 end-fraction Convert to improper fractions first: 15 and 10 by 5):

2110×1514=21×1510×1421 over 10 end-fraction cross 15 over 14 end-fraction equals the fraction with numerator 21 cross 15 and denominator 10 cross 14 end-fraction Simplify (21 and 14 by 7; 15 and 10 by 5): 3×32×2=94=214the fraction with numerator 3 cross 3 and