using ZipFile r = ZipFile.Reader("your_file.zip") for f in r.files println("Filename: $(f.name)") # Read content as a string content = read(f, String) end close(r) Use code with caution. Copied to clipboard
a = [1, 2, 3] b = ["A", "B", "C"] # This creates an iterator of tuples: (1, "A"), (2, "B"), etc. zipped = zip(a, b) Use code with caution. Copied to clipboard Quick Reference Table Recommended Package Key Feature ZipFile.jl Standard archive reading/writing Streaming GZip CodecZlib.jl Robust, part of TranscodingStreams.jl Simple GZip Thin wrapper around C zlib functions
If you are working with Julia and need to handle .zip or .gz (gzip) files, there are several standard packages you can use depending on your specific needs. 1. Handling ZIP Archives julia g.zip
GitHub - JuliaIO/GZip.jl: A Julia interface for gzip functions in zlib
Note that Julia also has a built-in zip() function, but it is used for , not for file compression. using ZipFile r = ZipFile
How to read files from a compressed file (zip/gz) lazily? - New to Julia - Julia Programming Language
using GZip fh = GZip.open("test.gz", "w") write(fh, "compressed text") close(fh) Use code with caution. Copied to clipboard 3. Julia's Built-in zip Function How to read files from a compressed file (zip/gz) lazily
For creating or reading standard .zip files (archives containing one or more files), the ZipFile.jl and ZipStreams.jl packages are the primary options.
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