B.p Geidman 4 Klass 1 Polugodie Urok 51 Str 94 Zadacha 5 Reshenie Apr 2026

B.p Geidman 4 Klass 1 Polugodie Urok 51 Str 94 Zadacha 5 Reshenie Apr 2026

To find how far the train went, multiply its speed by its travel time: 60×3=180 (km)60 cross 3 equals 180 (km) 3. Determine the bus's distance

The problem describes a journey involving a train and a bus. We know: The train traveled for hours at a speed of The bus traveled for The total distance covered by both was 2. Calculate the train's distance To find how far the train went, multiply

The solution to task 5 on page 94 (Lesson 51) of B.P. Geidman's 4th-grade mathematics textbook (1st half-year) is . 1. Identify the given values Calculate the train's distance The solution to task

Subtract the distance covered by the train from the total distance to find the remaining distance covered by the bus: 260−180=80 (km)260 minus 180 equals 80 (km) 4. Calculate the bus's speed Identify the given values Subtract the distance covered

To find the speed of the bus, divide the distance it traveled by its travel time: 80÷2=40 (km/h)80 divided by 2 equals 40 (km/h) Ответ The distance covered by the bus is , and its speed is