log2(2x−4)>log2(8)log base 2 of open paren 2 x minus 4 close paren is greater than log base 2 of 8 Since the base
For the logarithm to be defined, its argument must be strictly positive: 2x−4>02 x minus 4 is greater than 0 2x>42 x is greater than 4 x>2x is greater than 2 log2(2x−4)>log2(8)log base 2 of open paren 2 x
.The solution to the quadratic inequality is the interval between the roots: -1 Answer : А.П. Ершова, В.В. Голобородько log2(2x−4)>log2(8)log base 2 of open paren 2 x
Rewrite the constant 3 as a logarithm with base 2: log2(2x−4)>log2(8)log base 2 of open paren 2 x
log2(2x−4)>log2(23)log base 2 of open paren 2 x minus 4 close paren is greater than log base 2 of open paren 2 cubed close paren
log0.5(x+1)≥-2log base 0.5 of open paren x plus 1 close paren is greater than or equal to negative 2 The argument must be positive:
lg(x2−3)