Algebra 9 Klass Mordokovich Domashniaia Kontrolnaia Rabota 2 Reshenie (Original)

x2+25−10x+x2=13x squared plus 25 minus 10 x plus x squared equals 13

Multiply one or both equations by numbers so that the coefficients of one variable become opposites (e.g., -5ynegative 5 y Add the equations to eliminate that variable. x2+25−10x+x2=13x squared plus 25 minus 10 x plus

x2+(5−x)2=13x squared plus open paren 5 minus x close paren squared equals 13 x2+25−10x+x2=13x squared plus 25 minus 10 x plus

{x+y=5x2+y2=132 cases; Case 1: x plus y equals 5; Case 2: x squared plus y squared equals 13 end-cases; From the first equation: Step 2: Substitute x2+25−10x+x2=13x squared plus 25 minus 10 x plus